Math, asked by Missekta, 22 days ago

On a particular day in Manali, the temperature was 17 °C at 6 p.m. If the temperature dropped
steadily at a rate of 1 °C per hour, what was the temperature at 11 p.m.?​

Answers

Answered by Abhijaybishnoi
5

Answer:

Temperature at 6p.m= 17℃

Time gap b/w= 6p.m and 11p.m= 11p.m-6p.m=5hours

Temperature dropped=5hours ×1℃=5℃

Temperature at 11p.m= 17℃-5℃=12℃

Step-by-step explanation:

MARK AS BRAINLIEST

Answered by Deepansha1749
2

Answer:

I don't know the answer but I will try

Step-by-step explanation:

If the temperature is dropped 1 degree Celsius then at 6 pm- 17degree Celsius

7pm- 16 degree Celsius

8pm - 15 degree Celsius

9 pm - 14 degree Celsius

10 pm - 13 degree Celsius

and at 11 pm it will be at 12 degree Celsius

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