On a particular day , the maximum frequency reflected from the ionsphere is 10 MHz. On another day , it was found to decrease to 8 MHz. Calculate the ratio of the maximum electron densities of the ionosphere on the two days .
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Answer:
Explanation :
The maximum frequency reflected from the ionosphere,
The relation between electron density of ionosphere and the frequency is :
f_c=9\sqrt{N_{max}}f
c
=9
N
max
where,
N_{max}N
max
is the maximum electron density in ionosphere.
f_cf
c
is the critical frequency.
N_{max}=\dfrac{f_c^2}{(9)^2}N
max
=
(9)
2
f
c
2
N_{max}=\dfrac{(10^7\ Hz)^2}{(9)^2}N
max
=
(9)
2
(10
7
Hz)
2
N_{max}=\dfrac{10^{14}}{81}N
max
=
81
10
14
N_{max}=0.012\times10^{14}/m^3N
max
=0.012×10
14
/m
3
Hence, this is the required solution.
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