On a particular day the number of vehicles passing through a crossing is as follows. Two wheelers = 57; Three wheelers = 33; Four wheelers = 30. A particular vehicle is chosen at random, what is the probability that it is not a four wheeler.
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Given:
Number of two-wheelers = 57
Number of three-wheelers = 33
Number of four-wheelers = 40
To Find:
The probability that it is not a four-wheeler.
Solution:
Calculating total number of vehicles = Two wheeler + Three wheeler + Four wheeler
= 57 + 33 + 40
= 120
Number of vehicles which are not four wheelers -
= 57 + 33
= 90
Probability that it is not a four wheeler -
= 90/120
= 3/4
Answer: The probability that it is not a four-wheeler is 3/4
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