Question

On a planet a freely falling body takes 2 seconds when dropped from a height of 32 metres if the time period of a simple pendulum us 2π seconds.Then its length on the planet is

Answer 1

Answer:

S = 1/2 g t^2

g = 2 * S / t^2 = 64 / 4 m/s^2  = 16 m/s^2    on the planet

P = 2 * pi * (L / g)^1/2      period of pendulum

2 * pi =  2 * pi * (L / g)^1/2

L = g = 16 m