Question

On a planet a freely falling body travels 10 m, and 90 m in 1 second and 3 seconds respectively
Acceleration due to gravity on that planet is

a)20ms-2
b) 10 ms-2
d) 4.9 ms-2
c) 9.8 ms-2​

Answer 1

Answer:

Initial velocity of the body u=0

Distance covered in n

th

second, S

n

=u+

2

1

g(2n−1)

∴ S

n

=

2

1

g(2n−1) (as u=0)

Distance moved in 1

st

second i.e. n=1, S

1

=

2

1

g(2×1−1)=

2

1

g

Distance moved in 2

nd

second i.e. n=2, S

2

=

2

1

g(2×2−1)=

2

3

g

Distance moved in 3

rd

second i.e. n=3, S

3

=

2

1

g(2×3−1)=

2

5

g

⟹ S

1

:S

2

:S

3

=1:3:5