Question

On a planet a freely falling body travels 10m,and 90m in 1 second and 3 seconds respectively. Acceleration due to gravity on that planet is
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Answer 1

Answer:

gravity on that planet is 20m/s2

Explanation:

see the attachment!!!

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Answer 2

The correct answer is 20 $\frac{m}{sec^{2} }$.

Given: Distance covered by freely falling body on other planet = 10m and 90m.

Time taken to fall = 1 and 3 seconds.

To Find: Acceleration due to gravity on that planet.

Solution:

For case 1: s = 10m, t = 1 sec, u = 0(free fall).

$s=ut+\frac{1}{2}at^{2}$

$10=0(1)+\frac{1}{2}a*1^{2}$

a = 20 $\frac{m}{sec^{2} }$.

For case 2: s = 90m, t = 3 sec, u = 0(free fall).

$s=ut+\frac{1}{2}at^{2}$

$90=0(1)+\frac{1}{2}a*3^{2}$

a = 20 $\frac{m}{sec^{2} }$.

Hence, the acceleration due to gravity on that planet is 20 $\frac{m}{sec^{2} }$.

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