On a railway line there are 20 stops. A ticket is needed to travel between any two stops. How many different tickets can be prepared to cater to all the travel possibilities?
Answers
The number of different tickets can be prepared to cater to all the travel possibilities= 380
Explanation:
Given : The number of stops in a railway line = 20
A ticket is needed to travel between any two stops.
To travel between two stops , the passenger need to reach one stop by himself.
Number of choices to reach any stop = 20
Then, the number choices for stations remained for him = 19
Now , the number of different tickets can be prepared to cater to all the travel possibilities = 20 x 19 = 380
Hence, the number of different tickets can be prepared to cater to all the travel possibilities= 380
# Learn more :
A box contains 20 tickets of identical appearance, the tickets being numbered 1, 2, 3, ….., 20. in how many ways can 3 tickets be chosen such that the numbers on the drawn tickets are in arithmetic progression ?
https://brainly.in/question/1342238
The second book is also right if you look at this question the other way.
Suppose the 20 stations are A,B, C, D,….. T
If you get in the train on station A, it will go to T thorough B,C,D, and so on. So, from A till T we need 20 tickets.
If you get on the train on station B, it will go to T thought C, D ,E and so on. So, from B, we need 19 tickets.
Similarly, this pattern will go on till station T where we need only 1 ticket.
Therefore the answer will be 20+19+18.. 1 = 210
But if you assume that the train will travel to every station from every other station, then the answer will be 20*19=380
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