on a rainy day, rain is falling vertically downward with speed of 3ms^-1. A boy is standing on the ground and wind started blowing with a speed of 10ms^-1. in west to east direction. In what direction, he should hold umbrella to protect himself from rain.
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Answer:
Given,
speed of rain is 35m/s
Speed of wind is 12m/s
The resultant velocity of raindrops will be the vector sum of the raindrop speed (vertical) and the horizontal wind speed.
The magnitude of the resultant velocity of the raindrops is:
(12
2
+35
2
)
=37m/sec
the direction of the resultant velocity vector with the vertical
=tan
−1
(
35
12
)=18.92
0
.
The umbrella should be pointed in the direction opposite to the resultant velocity of the raindrops. So it should be in the direction 18.92
0
. the inclination to the vertical opposite to the direction of wind., towards East.
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