Question

On a rod AD forces 10N, 10N, 20N, 15 N acts at points A, B, C, D. Forces 10N, 10N, 15 N acts downwards and 20 N acts upwards. The position of the points B, C, D from A are 20mm, 30mm, and 50mm respectively. The equivalent force couple system at A is *​

Answer 1

Answer:

thanks for the update and for the record I

Answer 2

Answer:

The equivalent force couple system at A is 50 Nmm

Explanation:

Force couple or moment is the product of perpendicular force and distance , i.e.

M= F×d

Let's take clockwise direction as positive

M(about A) = M(at b )+M(at c )+M(at d)

M(about A)=Force( at B)×d1+Force( at C)×d2+Force( at D)×d3

where,

• d1=20mm , Force( at B)=10N
• d2=30mm,Force( at C)=20N
• d3=50mm,Force( at D)=15

M(about A)= 10×20+20×30-15×50

M(about A)=50 Nmm or 50 Newton Milimeter

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