on a see saw two children of masses 25 kg and 50 kg are sitting on one side of it a distance 2 m and 1.5 m respectively from its middle. Where should a man of mass 75 kg sit to balance it?
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Answer:
1 . 76 m from the pivot point.
Explanation:
NOTE : CONVERT KG ( MASS ) TO NEWTONS ( FORCE )
25 kg . 10 = 250 N
50 kg . 10 = 500 N
75 kg . 10 = 750 N
( F 1 . D 1 ) + ( F 2. D 2 ) = F 3. D 3
( 250 . 2 ) + ( 500 . 1.5 ) = 750 . X
500 + 750 = 750 X
1250 = 750 X
1250 / 750 = X
1 . 67 m = x
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