On a see saw, two children of masses 30kg and 60kg are sitting on one side of it at a distance of 2m and 2.5m respectively from the centre of the see saw. Find the distance at which a man of mass 75 kg should sit on the other side to balance the see saw.
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himanshim492p30o1x:
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Answer:
2.8m
Explanation:
let let the 75kg man sit at a distance of X metre from the middle of the seesaw.
according according to principle of moments
anticlockwise moment = clockwise moments.
=> ( 60kgf * 2.5m ) +( 30kgf * 2m )= 75kgf * Xm
=>150kgfm + 60kgfm = 75 kgfm
=> 210kgfm = 75 kgfm
=>X m = 210kgfm / 75 kgf
=>X m= 2.8 m.
therefore the distance at which a man of mass 75 kg should sit on the other side of the SeeSaw to balance it is 2.8m
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