on a see -saw two sisters of masses 20kg and 30kg on one side of it at distance 1m and 2m respectively from the fulcrum.where should their father of mass 80 kg sit in order to balance them?
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Answer:
Mass of the man m=40kg
Acceleration of lift in upward direction a=2m/s
2
Let the weight shown by machine be N.
Equation of motion for the body : ma=N−mg
We get N=m(a+g)
∴ N=(40)(2+10)=480 N
Thus weight of the man recorded by machine W
′
=
g
N
∴ W
′
=
10
480
=48 kg
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