Question

On a seesaw, two children of masses 30kg and 50kg are sitting on one side of it at distances 2m and 2.5m respectively from its middle. Where should a man of mass 74kg sit to balance it?​

Answer 1

Answer:

Explanation:

$Torque=mgr$

Torque provided by the children is opposed by the torque provided by the man sitting on the other side of the seesaw

$(30)(g)(2)+(50)(g)(2.5)=(74)(g)(x)\\60+125=74x\\185=74x\\x=2.5m$