Question

On a ship sailing in Pacific Ocean where temperature is 23.4 degree Celsius a balloon is filled with 2L air. What will be the volume of the balloon when the ship reaches Indian Ocean, where temperature is 26.1 degree Celsius ?​

Answer 1

V₁ = 2L

T₂ = 26.1 + 273 = 299.1K

T₁ = (23.4 + 273)K

T₁ = 296.4K

     

• From Charles Law,  

V₁  ÷  T₁ = V₂ ÷ T₂

V₂ = V₁T₂/T₁

V₂ = 2L * 299.1K/296.4K

V₂ = 2L * 1.009

V₂ = 2.018L

Answer 2

The Volume of the balloon will be 2.018L when the ship reaches Indian Ocean, where temperature is 26.1°C

Given,

A ship sailing in Pacific Ocean where temperature is 23.4°C

A balloon is filled with 2L air.

The temperature of Indian Ocean is 26.1°C

To Find,

Find the the volume of the balloon when the ship reaches Indian Ocean, where temperature is 26.1°C

Solution,

Let assume that,

Volume of the balloon is, $V_{1}$ = 2L

Temperature of Pacific Ocean is,

$T_{1}$= 273+ 23.4= 296.4 K

and,

Temperature of Indian Ocean is ,

$T_{2}$= 273+ 26.1= 299.1 K

We have to find, the volume of the balloon,

$V_{2}$= ?

According to the Charles Law,

" a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant."

so,

$\frac{V_{1} }{V_{2} } = \frac{T_{1} }{T_{2} }$

or , $V_{2} = \frac{V_{1} T_{2} }{T_{1} }$

or, $V_{2} = \frac{2*299.1}{296.4}$ = 2*1.009 = 2.018 L

Hence, The Volume of the balloon will be 2.018L when the ship reaches Indian Ocean, where temperature is 26.1°C

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