On a single throw of three dices find the probability of getting 1) the same no. On all the three dice 2) not getting the same no. Meritnation
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HEY MATE HERE IS YOUR ANSWER
Imagine rolling the dice one at a time. We don't care which number we see, so we don't care about the outcome of the roll of the first die; it just tells us what we're looking for.
Whatever that number is, the chances that the second die comes up on it is 1/6
The chances that the third die comes up with it is also 1/6
So the chances that both the second and third dice come up with the same number that's on the first is 1/6 × 1/6 = 1/36
Imagine rolling the dice one at a time. We don't care which number we see, so we don't care about the outcome of the roll of the first die; it just tells us what we're looking for.
Whatever that number is, the chances that the second die comes up on it is 1/6
The chances that the third die comes up with it is also 1/6
So the chances that both the second and third dice come up with the same number that's on the first is 1/6 × 1/6 = 1/36
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