Question

On a smooth horizontal surface a block A of mass 10kg is kept.On this block a second block B of mass 5kg is kept. The coefficient of friction between the two blocks is 0.4. A horizontal force of 30N is applied on the lower block. find the force of friction between the blocks​

Answer 1

ǟռֆաɛʀ :

From fig 1

30 - fs = 30a

From fig 2

Fs = Nu

= (5g) (0.4)

= 20 N

So 20 = 5ab

=> ab = 4 m/s2

and friction = 20 N between blocks

Answer 2

Given:

• On a smooth horizontal surface a block A of mass 10kg is kept
• On this block a second block B of mass 5kg is kept
• The coefficient of friction between the two blocks is 0.4
• A horizontal force of 30N is applied on the lower block

According to the given data,

• ($\sf\purple{Refer \ the \ image \ for \ diagram}$)

To Find:

• Force of friction between the blocks

We have,

• $\rm M_{1} = 10kg$
• $\rm M_{2} = 5kg$
• $\rm F = 30N$
• $\rm g = 10m/sec^2$

Now, By using force of friction formula

$\implies\:\:{\boxed{\rm{Force\: of\:friction\:=\:\dfrac{M_{2}F}{M_{1}+M_{2}}}}}$

$\implies\:\:\rm Force\: of\:friction\:=\:\dfrac{5\times 40}{10+5}$

$\implies\:\:\rm Force\: of\:friction\:=\:\dfrac{150}{15}$

$\implies\:\:\rm Force\: of\:friction\:=\:10N$

$\therefore\:\rm Force\:of\:friction\:between\:the\:blocks\:is\:10N$