On a smooth plane surface (Figure below) two blocks A and B are accelerated up by applying a force 15 N on A. If mass of B is twice that of A, then force on B is
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F= m1 ×a. F=m2 ×a.
a = F / m1. a = F / m2
by computing a and a ...
F/m1. = F/m2. == since m2 = 2× m1.
thus. 15/ m1 = F/ 2× m1...
therefore after calculating ..... F on B = 30N
I hope this will help you........☺️☺️
a = F / m1. a = F / m2
by computing a and a ...
F/m1. = F/m2. == since m2 = 2× m1.
thus. 15/ m1 = F/ 2× m1...
therefore after calculating ..... F on B = 30N
I hope this will help you........☺️☺️
Answered by
0
Answer:
30N
Explanation:
F= m1 ×a. F=m2 ×a.
a = F / m1. a = F / m2
by computing a and a ...
F/m1. = F/m2. == since m2 = 2× m1.
thus. 15/ m1 = F/ 2× m1...
therefore after calculating ..... F on B = 30N
I hope this will help you
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