Question

On a square track of edge length 100 m, an athlete
starts from one corner and reaches diagonally
opposite corner. Find the distance and the
magnitude of displacement of the athlete.​

Answer 1

Answer:

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your answer is here !

Explanation:

The distance will be equal to length of two sides which he covered i.e. = 100 m + 100m

=> 200 m

Displacement = LENGTH OF DIAGONAL

=√(100 square + 100 square)

= √ (10000+10000)

=√20000

=> √20000 m

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Answer 2

As distance is the actual distance covered by the object

D=100+100=200m

As displacement I the shortest distance covered between the initial and the final position

disp=√(100)²+(100)²

disp=√2×10^8

disp=1.4×10^4

I hope this helps ( ╹▽╹ )