Question

On a square track of edge length 100m, an athlete starts from one corner and reaches diagonally opposite corner. Find the distance and the magnitude of displacement of the athlete.​

Answer 1

Answer:

Distance => 200m

Displacement => 141.42m

Explanation:

Given :

• Athlete starts from one corner of the square of side 100m and reaches to the diagonally opposite corner.

To Find :

• Distance travelled and the magnitude of the displacement.

Solution :

Athelete start from one corner,let that corner be “A” and reaches diagnolly opposite corner (B).

It means two sides (AB and BC) was travelled by the athlete.

So,

Total distance travelled   by athlete => (100 + 100)m

= 200m

and displacement,

$\implies \sf{}\sqrt{100^2+100^2}$

$\implies \sf{}\sqrt{10000+10000}$

$\implies \sf{}\sqrt{20000}$

$\therefore\sf{}141.42m$

Hence,distance travelled by the athlete is equal to 200m  and displacement is equal to 141.42m.

Answer 2

Answer:

Here athlete starts from one corner and reaches diagonally opposite corner. Displacement is equal to the length of diagonal of the square \(=\sqrt{(100)^2+(100)^2}=100\sqrt{2}\ m\).

Step-by-step explanation:

PLS MARK ME AS BRAINLIEST