Question

On a track racing car a completes the track in 28 minutes while racing car be complete it in 24 minutes after how many minutes will they be side-by-side again

Answer 1

Do L.C.M. of 24 and 28 .
2 |24,28
2 |12,14
2 |6,7
3 |3,7
7 |1,7
|1,1 So least common multiple of 24 and 28 are 2×2×2×3×7=168. In 168 minutes one racing car completes 6 complete circulations and another racing car completes 7 complete circulations So they can be side-by-side again initially at where they started . Hope it helps you. Please mark me as Brainliest.

Answer 2

Answer:

Therefore we need to find the Lcm of the minute to find out when they will be side by side again

Step-by-step explanation:

Do L.C.M. of 24 and 28 .

2 |24,28

2 |12,14

2 |6,7

3 |3,7

7 |1,7

|1,1 So least common multiple of 24 and 28 are 2×2×2×3×7=168. In 168 minutes one racing car completes 6 complete circulations and another racing car completes 7 complete circulations So they can be side-by-side again initially at where they started. Hope it helps you.

Please mark me as Brainliest