Question

On a uniform meter rule of weight 50gf is pivoted at 45cm mark weights of 40gf and 60gf are hanging at 10cm and 60cm marks then which mark should we hang a weight of 100gf to balance it .​

Answer 1

Answer:

Let a wt. of 80gf be placed at a distance x from 40cm mark.  

Clock wise moments = Anticlock wise moment  

(80 × x) + 50 × (50 – 40)

= 100 × (40 – 5)  80x +500

= 3500  80x = 3500 – 500

= 3000  x = 3000/80 = 37.5cm  

∴ A is at 40 + 37.5 = 77.5cm