On adding 1 g arsenic to 80 g benzene, the freezing
point of benzene is lowered by 0.19°C. The
formula of arsenic is (K, = 5.08 K kg mol-').
Answers
Answer:
g of arsenic dissolved in 86 g of benzene brings down the freezing point to
from
.If
of benzene is
, the atomicity of the molecule is : (As =75 or As GAM 75)
Answer:
The formula of arsenic is As₄.
Explanation:
Given:
ΔTf = 0.19°c
Kf = 5.08 K kg/mol
The depression in the freezing point depends on the concentration of the solute in a solution and is related to molality as below.
ΔTf = i × Kf × molality
where Tf is the lowering in freezing point;
i is the Van't Hoff factor and
Kf is the molal depression constant or cryoscopic constant.
Substituting the values in the above equation.
0.19 = i×5.08×(1000×1/80×75)
= i×5.08 × 12.5/75
i = 0.22
α = (i-1)/(1/n-1) = 1
α is the degree of association.
i-1 = 1/n - 1
i = 1/n
n = 1/i
= 4.4
The formula of arsenic is As₄.
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