Question

On adding dilute hydrochloric acid to copper oxide powder, the solution formed is blue-green.
(a) Predict the new compound formed which imparts a blue-green colour to solution.
(b) Write a balanced chemical equation of the reaction which takes place.
(c) On the basis of the above reaction, what can you say about the nature of copper oxide?

Answer 1

Answer:

The obtained compound is Copper(II) chloride (CuCl2)

Explanation:

(a) On adding dilute Hydrochloric acid to copper oxide powder, The new compound formed is copper(II) chloride (CuCl2) which imparts a blue green Colour to the solution.

(b) The balanced chemical equation of the reaction which takes place is as follows:

      $Cuo + 2HCl$→$CuCl_{2} +H_{2}O$

      (copper oxide )          (copper(II) chloride)        

(c) copper(II) oxide or cupric oxide is the inorganic compound with the  formula Cuo. which is a black solid and it is a one of the two stable oxides of copper.

  Here, In the above equation(b) The oxidation state of copper remains same in the products and also in the reactants i.e,(+2). where as the copper(II) chloride is a blue green crystalline solid, when its diluted aqueous solution has a pale blue colour.

Answer 2

Copper Chloride Gives Blue green Color

Explanation:

• The new compound formed is copper(II) chloride ($CuCl_2$), which imparts blue-green colour to the solution.

$CuO + 2HCl ---> CuCl_2 + H_2O$

Copper Oxide      Copper (II) Chloride  

                               (blue green)

b.) The Balanced Equation for the reaction is as under -

$CuO + 2HCl -----> CuCl_2 + H_2O$

Copper Oxide      Copper (II) Chloride  

                               (blue green)

Which says that the Reactants on Left hand side of equation are equal to the Product side or the reaction.

c.) Copper II oxide which is also called as cupric oxide is inorganic in nature. (Colour is Black)