On an average, 96 patients per 24-hour day require the service of an emergency clinic. also, an average patient requires 10 minutes of active attention. assume that the facility can handle only one emergency at a time.
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Data: λ= 96 / 24 = 4 patients per hour., µ= (1 / 10) ± 60 = 6 patients per hour. Hence)/(µλ=ρ= 4 / 6 = 2 / 3.Average number of patients in waiting line = E(L) = )1/(2ρ−ρ= (4 / 9) / [1 ° (2 / 3)] = 4 / 3patients. = One and one third patients. Now this is to be reduced to 1/2 = E’(L).E’(L) = )/()/(λ−µλ×µλ’’or1/2 = )4/4()/4(−µ×µ’’or ’’µ−µ42° 32 = 0 or )()8(µ+µ−µ’’= 0 or ’µ= 8 patients perhour.(Note ’µ= °4 is not considered as it does not convey any meaning.)Therefore, average time required by each patient = 1/8 hour = 15 / 2 minutes = 7 ‰ minutes.Decrease in time required by each patient 10 ° (15 / 2) = 5 / 2 minutes or 2 ‰ minutes.
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Data: λ= 96 / 24 = 4 patients per hour., µ= (1 / 10) ± 60 = 6 patients per hour. Hence)/(µλ=ρ= 4 / 6 = 2 / 3.Average number of patients in waiting line = E(L) = )1/(2ρ−ρ= (4 / 9) / [1 ° (2 / 3)] = 4 / 3patients. = One and one third patients. Now this is to be reduced to 1/2 = E’(L).E’(L) = )/()/(λ−µλ×µλ’’or1/2 = )4/4()/4(−µ×µ’’or ’’µ−µ42° 32 = 0 or )()8(µ+µ−µ’’= 0 or ’µ= 8 patients perhour.(Note ’µ= °4 is not considered as it does not convey any meaning.)Therefore, average time required by each patient = 1/8 hour = 15 / 2 minutes = 7 ‰ minutes.Decrease in time required by each patient 10 ° (15 / 2) = 5 / 2 minutes or 2 ‰ minutes.
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