On an object of mass 1 kg moving along x axis with constant speed 8m/s, a constant force 2N is applied in positive y-direction. Find its speed after 4 seconds.
Answers
Answered by
38
Velocity along x-axis = 8 m/s
a = F/m
= 2/1
= 2 m/s^2
Velocity along y-axis after 4s = u + at
= 0 + 2*4
= 8 m/s
Magnitude of resultant velocity after 4s = √(v_x^2 + v_y^2)
= √(8^2 + 8^2)
= 8√2 m/s
It’s speed after 4s is 8√2 m/s
a = F/m
= 2/1
= 2 m/s^2
Velocity along y-axis after 4s = u + at
= 0 + 2*4
= 8 m/s
Magnitude of resultant velocity after 4s = √(v_x^2 + v_y^2)
= √(8^2 + 8^2)
= 8√2 m/s
It’s speed after 4s is 8√2 m/s
Answered by
23
in case of any query ask me
mark me brainliest if it helped u
mark me brainliest if it helped u
Attachments:
Similar questions