Question

on an object of mass 1 kg moving along x-axis with constant speed 8 m/s, a constant force
2 N is applied in positive y-direction. Find its speed after 4 seconds.​

Answer 1

Answer:

Given,

Horizontal velocity is 8î .

vertical force 2 N.

We know that,

                        F = ma

                        2   = 1 × a

                         a = 2 m/s^2

   

Kinematics formula

       v = u + at

         = 8î + 2j × 4

         = 8i + 8j

now in magnitude = √( 8^2 + 8^2 )

                              = 8√2 m/s