Question

On an object of mass 1 kg moving along x-axis with constant speed 8 m/s, a constant force 2N is applied in positive y-direction. Find its speed after 4 seconds.​

Answer 1

Vx = 8 { velocity in x - axis )
Fy = 2N { force act on body in y-direction }

we know,
F = ma
2 = 1 × a
a = 2 m/s² In y - direction ,

now, use vector kinematics formula
V = U + at
here,
U = 8i
a = 2j
t = 4

V = 8i + 2j × 4 = 8i + 8j
hence, final velocity = 8i + 8j
we know, speed = | velocity|
speed = √(8² +8²) = √(2×8²)
= 2√8 m/s

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