on an object of mass 1kg moving along x-axis with constant speed 8m/s a constant force 2N is applied in positive y direction find the speed after 4s
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Answer:
√(65) m/s
Step-by-step explanation:
Acceleration along vertical axis is
a = F/m
= 2 N / (8 m/s)
= 0.25 m/s²
Velocity along vertical axis (positive y direction) after 4 s is
vy = uy + at
= 0 + (0.25 × 4)
= 1 m/s
Magnitude of resultant velocity after 4 s is
V = √(vx² + vy²)
= √(8² + 1²)
= √(65) m/s
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