Question

on an object of mass 1kg moving along x-axis with constant speed 8m/s a constant force 2N is applied in positive y direction find the speed after 4s ​

Answer 1

Answer:

√(65) m/s

Step-by-step explanation:

Acceleration along vertical axis is

a = F/m

= 2 N / (8 m/s)

= 0.25 m/s²

Velocity along vertical axis (positive y direction) after 4 s is

vy = uy + at

= 0 + (0.25 × 4)

= 1 m/s

Magnitude of resultant velocity after 4 s is

V = √(vx² + vy²)

= √(8² + 1²)

= √(65) m/s