Question

On analysis it was found that the black oxide of copper and red oxide of copper contains 80% and 89% of copper respectively. Show that this data is in agreement with the law of multiple proportions.

Answer 1

in black oxide the % of Cu = 80% , so % of O = 20%
hence if % of Cu = 1 , the % of O = 20/80 = 0.25

in red oxide % of Cu = 89% , so % of O = 11%
hence if % of Cu = 1 , the % of O = 11/ 89 = 0.1235

ratio of O:O in the two oxide are = .25/.25 : 0.1235/0.25 = 1: 0.5 = 2: 1
which is a ssimple whole no. ratio hence the law of multiple proportion .

Answer 2

Answer:

On analysis it was found that the black oxide of copper and red oxide of copper contain 80% and 89% of copper respectively. Show that this data is in accordance with law of multiple proportions. Hint : The ratio of Cu combining with fixed weight of oxygen in black and red oxide is 1:2.