Physics, asked by anshv8488, 1 day ago

on and electric bulb auto 240V - 60 what is printed then resistance of its filament will be​

Answers

Answered by 29muskanbishnoi
0

Answer:

807 ohm

Explanation:

electric bulb rated 60W , 220V

Resistance of its filament is given using P = V² / R

then R = V² / P

(220)²/60 = 807 ohm

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