Question

On and on object of mass 1 kg moving with constant speed 8 metre per second square and a constant force is applied in the positive direction find the speed after 4 seconds

Answer 1

Hi,

Thank you for posting your question on embibe. Hope your prep is going well.

Here is the answer to your question:

Vx = 8

Fy = 2N

It is known to us that,

F = ma

2 = 1 × a

a = 2 m/s² In y - direction ,

by using vector kinematic formula we'll get

V = U + at

Given Here

U = 8i

a = 2j

t = 4

V = 8i + 2j × 4 = 8i + 8j

⇒ Final velocity = 8i + 8j

Speed = | velocity|

Speed = √(8² +8²)

= √(2×8²)

= 2√8 m/s

Answer 2

Answer:

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