Question

On annual day of a school, 400 students participated in the function. Frequency distribution showing their ages is as shown in the following table :

Answer 1

but where is the table ?

Answer 2

Answer:

mean=10.17 ,median=9.625

mean=A+Σfiui/Σfi*h

mean=12+[-366/400]*2

mean=12-1.83=10.17

median=9+[200-190/32]*2

            =9+5/8

           = 9+.625

            =9.625