Question

On annual day of school, 400 students participated in the function. Frequency distribution showing their ages is as shown in the following table

Answer 1

Here, the summation of Fi is equal to 400 and summation of FiDi is equal to -732. Hence, the mean is equal to 12- 732/400 = 10.17 .

Therefore, the  median is equal to 9 + ( 10/32) * 2 which is equal to 9.625. The median class is 9-11. Median is 9.625.