Question

On any given day, the probability that bob will
have breakfast is more than 0.6. the
probability that bob will have breakfast and
will have a sandwich for lunch is less than 0.5.
the probability that bob will have breakfast or
will have a sandwich for lunch equals 0.7. let
р = the probability that, on any given day, bob
will have a sandwich for lunch. if all the
statements are true, what possible range can
be established for p?
(a) 0 < p < 0.6
(b) 0 < p < 0.6
(c) O sp < 0.6
(d) 0 < p < 0.7
(e) 0 < p < 0.7

Answer 1

Given :   the probability that bob will have breakfast is more than 0.6. the

probability that bob will have breakfast and will have a sandwich for lunch is less than 0.5. the probability that bob will have breakfast or

will have a sandwich for lunch equals 0.7.  

To find :  probability that, on any given day, bob will have a sandwich for lunch

Step-by-step explanation:

probability that bob will have breakfast  B >  0.6

probability that bob will have breakfast and will have a sandwich for lunch ( B & L )  <  0.5.

=> P(B)P(L) <  0.5

breakfast or Lunch   =  P(B)  + P(L)  -  P(B)P(L)  = 0.7

P(L)  -  P(B)P(L)  = 0.7 - P(B)

P(B) >  0.6

P(L)  -  P(B)P(L)   < 0.1

=> P(L) < 0.1 + P(B)P(L)

P(B)P(L)  < 0.5

=> P(L)  <  0.6

Probability bob will have a sandwich for lunch.    <  0.6

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