Math, asked by biankaszukala8, 10 months ago

On Aoife’s 16th birthday, Buster was three times her age. On Aoife’s 21st birthday, how old was Buster?

Answers

Answered by yeipyeng04
2

Answer:53 years

Step-by-step explanation:

Aoife’s age = 16= x

Buster = 3x = 3 * 16

= 48

In r yrs, Aoife is 21

x + r = 21

16 + r =21

r = 21 - 16 = 5

In r yrs, Buster is:

48 + r

=>48 + 5

= 53 years

Answered by pragyagupta08
0

Step-by-step explanation:

On Aoife's 16 th birthday

Age of Aofie = x

Age of Buster = 3x

= x + 3x = 16

= 4x = 16

= x = 16 / 4

= x = 4

Therefore on Aoife's 16 birthday Buster was of 4 years .

On Aoife's 21st birthday

Age of Aoife = x

Age of Buster = 4

= x + 4 = 21

= x = 21 - 4

= x = 19

Hence,

It is proven that on Aoife's 16 th birthday Buster was of 4 years and on Aoife's 21 birthday Buster was of 19 years .

Ans : On Aoife's 21 birthday Buster was of 19 years .

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