on application
7. Find the LCM and HCF of
(a) x2 + 2x - 15 and 3x2 - 11x + 6
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a).
x²+2x-15=>
x²+5x-3x-15=x(x+5)-3(x+5)
(x-3)(x+5)
3x²-11x+6
3x²-9x-2x+6
3x(x-3)-2(x-3)
(x-3)(3x-2)
LCM-- (x-3)(x+5)(3x-2)
HCF-- (x-3)
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