Question

On applying a constant force on a body of mass 9 kg for 45 s, its velocity becomes 8 m s -1 from 3 m s -1 . if the direction of motion of the body remains unchanged, find the magnitude of force.

Answer 1

Answer:

1.2 N

Explanation:

m=9kg t=45s u=8 v=3 by Newton's 2nd Law of Motion, F=ma,

F=9 ×(v-u)/t

F =9× (-6/45)

F=-6/5N

=-1.2N

Magnitude is 1.2 N

Answer 2

Answer:        Force = 1N

Explanation:

• m= 9kg
• t= 45s
• u=3m/s
• v=8m/s

• F=?

                       ⇒F=ma

                       F=m(v-u/t)

                       F=9×(8-3/45)

                       F=9×5/45

                       F=9/9

                      F=1 N

plz mark the brainliest....