Question

on applying brakes, a cyclist travelling initially 2m/s comes to a halt at a constant retardation of 2 m/s^2. how much does the distance does the cyclist cover before coming to rest?​

Answer 1

Answer:

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Answer 2

Explanation:

v = u + at

v=0

u=2

a = - 2

t = 1 sec.

s = ut + (1÷2)(at^2)

s = 2×1 - 1

s = 1 m.

second mtd---

v^2 = u^2 + 2as