Question

on applying the pressure on a sphere by 20 x 10 (raised to 5)Pa, its volume decreased by 0.1%. The bulk modulus of the material of sphere is
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Answer 1

Given : on applying the pressure on a sphere by 20 x 10 ⁵ Pa, its volume decreased by 0.1%.

To Find : The bulk modulus of the material of sphere

Solution:

B= Pressure Applied / Fraction change in Volume

=> B = ΔP/(ΔV/V)

B: Bulk modulus

V = Initial Volume

ΔP = change in pressure / Pressure applied

ΔV = Change in Volume

ΔP = 20 x 10⁵ Pa

volume decreased by 0.1%

=> ΔV/V = 0.1%  = 0.001

=> B =  20 x 10⁵ /0.001

=> B = 20 x 10⁸  N/m²

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Answer 2

Question:

On applying the pressure on a sphere by 20x10 (raised to 5)Pa , its volume decreased by 0.1%. The bulk modulus of the material of spere is -:

Answer:

$\tt \: B = \frac{ Pressure \: applied }{ fraction \: change \: in \: volume }$

$\tt \: B = \frac{ ΔP }{ \frac{ ΔV }{ V } }$

B = Bulk Modulus

V = Initial Volume

$\tt \triangle P = \frac{change \: in \: pressure}{ pressure \: applied}$

$\tt \triangle V = change \: in \: volume$

$\tt \triangle P = 20 \times 1 {0}^{5} \: pa$

Volume decreased by 0.1%.

$\tt \ \frac { \triangle V}{V} = 0.1\% = 0.001$

$\tt \: B = \frac{20 \times {10}^{5} }{0.001}$

$\tt \: B = 20 \times {10}^{8} \: \frac{n}{ {m}^{2} }$