on ar rough S
is mou
mass 2K
A block of
akg
of coefficient of
frictional force on it
soving
friction
scroface
find the
0.5, find
Answers
Answer:
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Let 'p' be the force applied too at an angle θ
From the free body diagram
R+Psinθ−mg=0
R+Psinθ+mg...(i)
μR−pcosθ=0...(ii)
Equn.(i) is μ(mg−Psinθ)−Pcosθ=0
⇒μmg=μPsinθ−Pcosθ⇒p=
μsinθ+cosθ
μmg
Applied force P should be minimum, when μsinθ+cosθ is maximum
Again, μsinθ+cosθ is maximum when its derivative is zero
∴d/dθ(μsinθ+cosθ)=0
⇒μcosθ−sinθ=0⇒θ=tan
1
μ
So, P=
μsinθ+cosθ
μmg
=
cosθ
μsinθ
+
cosθ
cosθ
μmg/cosθ
=
1+μtanθ
μmgsecθ
=
1+tan
2
θ
μmgsecθ
=
secθ
μmg
=
(1+tan
2
θ)
μmg
=
1+μ
2
μmg
Minimum force is
1+μ
2
μmg
at an angle θ=tan
−1
μ
.