Question

On boiling, phosphorus with koh solution product formed is

Answer 1

The products formed are $PH_{3}$ (Posphane) and $KH_{2} PO_{2}$ (Potassium hypophosphite)

Explanation:

• 4P + 3 KOH + 3$H_{2} O_{}$ → $PH_{3}$ + 3 $KH_{2} PO_{2}$