Question

On cayo island monkeys are classified into 2 groups 'A' & 'B' suppose at the start of 2001 there where 100 monkeys in 'A' which become double after every 4 years.
There are 25 monkeys in group 'B' which become double after every 3 years. Find the total population of monkeys at the end of 2012.

Answer 1

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The work needed to be done is 156187 J.

Given :

Initial velocity(u) = 30 km/h = 30 × 5/18 = 25/3 m/s.

Final velocity(v) = 60 km/h = 60 × 5/18 = 50/3 m/s

Mass = 1500 kg

To Find :

Work needed to be done = ?

Solution :

We know the formula to calculate the work done,

So by using it,

➠ Work done = 1/2mv² - 1/2mu²

➠ W = m/2(v²-u²)

➠ W = 1500/2(50/3²-25/3²)

➠ W = 156187 J

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➤ Additional information :

Work is done when a force that is applied to an object moves that object or body!!

The work is calculated by multiplying the force by the amount of movement of an object itself !!

Formula = f × d

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Answer 2

Answer:

1200

Step-by-step explanation:

Group A population at the end of 2004=200

Group A population at the end of 2008=400

Group A population at the end of 2012=800

Group B population at the end of 2003=50

Group B population at the end of 2006=100

Group B population at the end of 2009=200

Group B population at the end of 2012=400

Total population at the end of the year 2012 = 800+400=1200

(Please mark me as the brainiest)