Question

On changing N₂ to N₂⁺, the dissociation energy of N–N bond
..... and on changing O₂ to O₂⁺ the dissociation energy of O–
O bond....
(a) increases, decreases (b) decreases, increases
(c) decreases in both cases(d) increases in both cases

Answer 1

Decreases and increases respectively.

Explanation:

• The bond dissociation energy is the amount of energy required to break the bond between the two atoms.

• The bond dissociation energy is directly proportional to bond order.

• Bond order is calculated as the half of difference between the total number of electrons in bonding orbital and antibonding orbital.

• In case of oxygen, the bond order is 2.

• In case of  O₂⁺, the bond order = \{10-5}{2}. =2.5

• In case of nitrogen, the bond order is 3.

• In case of N₂⁺, the bond order is \frac{9-4}{2}. = 2.5.

• So in case of oxygen, loss of one electron increased the bond order from 2 to 2.5 and in case or nitrogen, loss of 1 electron decreased the bond order from 3 to 2.5.

• So the bond dissociation energy in oxygen increased while in nitrogen decreased.

For more information about bond dissociation energy,

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Answer 2

Answer:

On changing N₂ to N₂⁺, the dissociation energy of N–N bond

..... and on changing O₂ to O₂⁺ the dissociation energy of O–

O bond....

(a) increases, decreases (

b) decreases, increases✔️

(c) decreases in both cases(d) increases in both cases