Question

On changing the length of a spring by 0.1 m there is a change of 5 J in its potential energy. The force constant of the spring is : (a) 80 Nm (6) 10.0 Nm (c) 90 Nm (d) 1000 N.m​

Answer 1

Answer:

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Answer 2

(d)The force constant of the spring is 1000 N.m.

Explanation:

For a spring, the expression for potential energy is given as

$U=\frac{1}{2}kx^2$.

Here, x is the amount of change in length of the spring and k is spring constant( force constant).

Given x = 0.1 m and U = 5 J.

Substitute the given values, we get

 $5J=\frac{1}{2}\times k(0.1)^2$

$k=\frac{10}{(0.1)^2}$

k = 1000 N.m

Thus, the force constant of the spring is 1000 N.m.

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