Question

On childrens day sweets were distributed equally among 540 children. but, on that day 120 children were absent. hence, each child got 4 more sweets. how many sweets were

Answer 1

The total no. of children = 540
The total no. of children absent = 120
Therefore,
The no. of children present = 540-120
= 420
The no. of sweets each child got = 4
Therefore,
The total no. of sweets = 420×4
= 1680


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Answer 2

Answer:

There were total 2100 sweets.

Step-by-step explanation:

Given,On childrens day sweets were distributed equally among 540 children.

So,total number of childrens = 540.

Now it also given that on that day 120 children were absent.

So,that day total number of childrens $= (540 - 120) = 420$

Again given,each child got 4 more sweets

Therefore each children got total (1+4) = 5 sweets.

So,there were total number of sweets

$= (420 \times 5) \\ = 2100$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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