On Claudia's birthday in 2004, her age was four times her brother's age on that day. On her birthday in 2005, her age was three times her brother's age on that day. In what year will Claudia's age, on her birthday, be twice her brother's age on that day?
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Answered by
6
Answer:
In 2008 Claudia's age will be twice as of her brother
Answered by
5
Answer:2008
Step-by-step explanation:
C, B ages of Claudia and brother in 2004.
Then C=4B AND (C+1)=3(B+1).
solving for two variables give C= 8 B=2.
Assume x years after 2004 Claudia becomes twice then 8+x=2(2+x). Solve for x.
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