On cm on the main scale of vernier callipers is divided into ten equal parts. If 20 division of vernier scale coincide with 8 small divisions of the main scale. What will be the least count of callipers ?
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Answer:
0.06 cm
Explanation:
least count(LC) = [1 main scale division(MSD) - 1 vernier scale division(VSD) ]
it is said that 10cm on the main scale is divided into 10 parts.
therefore 1MSD = 1 / 10 CM
ALSO , 20 VSD = 8 MSD
1 VSD = 8 / 20 MSD
LC = 1 MSD - 8/ 20 MSD
= MSD ( 1 - 4/10 ) (MSD = 1/10)
=3/50
=0.06.
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