Question

on combustion of 10 ml hydrocarbon 40 ml carbon dioxide and 50 ml water vapour was formed ...
hydrocarbons will be...
option up there in the clip​

Answer 1

${\huge {\mathfrak {Answer :-}}}$

➡️ Option (D) C4H10 - butane.

That's it..

Answer 2

C4H10+13/2O2------->4CO2+5H2O

So according to stoichiometry.

1 ml hydrocarbon can form 4 mol CO2

and 5 mol H20

So 10 ml will form 40 mlCO2 and 50ml H2O