Question

On combustion of Calciumcarbonate448L of volume of CO2 gas is produced.Howmany moles of CaCO3 is combusted and how many grams of CO2 gas is produced?​

Answer 1

Answer:

No.of moles of CaCO

3

=

100

50

=0.5

According to reaction, 1 mole of CaCO

3

gives 1 mole of CO

2

.

So 0.5 moles of CaCO

3

will give 0.5 moles of CO

2

Now at STP 1 mole of any gas = 22.4 L

So 0.5 moles of CO

2

gas = 22.4×0.5 = 11.2 L

Answer 2

Explanation:

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