Question

On comparing the ratios of the coefficients, find out whether the pair of equations x –

2y =0 and 3x + 4y -20 =0 is consistent or inconsistent​

Answer 1

Answer:

$x - 2y = 0 \\ 3x + 4y = 20$

Here, a1 = 1, a2 = 3, b1 = -2, b2 = 4, c1 = 0 and c2 = 20

So,

$\frac{a1}{a2} = \frac{1}{3} \: and \: \frac{b1}{b2} = \frac{ - 2}{4} = \frac{ - 1}{2} \\ \frac{a1}{a2} \: is \: not \: equal \: to \: \frac{b1}{b2}$

Therefore, the pair of equations is consistent and has a unique solution.

Hope it Helps ^_^

Answer 2

Answer:

Answer:

\begin{gathered}x - 2y = 0 \\ 3x + 4y = 20 \\ \end{gathered}

x−2y=0

3x+4y=20

Here, a1 = 1, a2 = 3, b1 = -2, b2 = 4, c1 = 0 and c2 = 20

So,

\begin{gathered} \frac{a1}{a2} = \frac{1}{3} \: and \: \frac{b1}{b2} = \frac{ - 2}{4} = \frac{ - 1}{2} \\ \frac{a1}{a2} \: is \: not \: equal \: to \: \frac{b1}{b2} \end{gathered}

a2

a1

=

3

1

and

b2

b1

=

4

−2

=

2

−1

a2

a1

isnotequalto

b2

b1

Therefore, the pair of equations is consistent and has a unique solution.

Step-by-step explanation:

hi